5dregensleyerjawabn nomer 1 sinA = 3/5 ( depa/mirig) depan = 3 , miring = 5 , samping = 4 cos B = samping/miring = 4/5 jawabn nomer 2 tan 45 = 1 jawabn nomer 4 mengguaka salah satu rumus bisa tang A dan bisa sinA sin a = 4√3 / 8 sin a = 1/2 √3 sin a = 60° jawabn nomer 5 sin135 = sin (180-45) = sin 45 = 1/2 √2 luas = 1/2 x a x b x sin 135 = 1/2 x 6 x 10 x 1/2 √2 = 3 x 5√2 = 15√2 cm² jawabn nomer 6 sudut = 60 : 2= 30 cos 30 = samping/miring 1/2 √3 = AP/5 1/2√3 x 5 = AP 5/2√3 = AP
sinA = 3/5 ( depa/mirig)
depan = 3 , miring = 5 , samping = 4
cos B = samping/miring
= 4/5
jawabn nomer 2
tan 45 = 1
jawabn nomer 4
mengguaka salah satu rumus bisa tang A dan bisa sinA
sin a = 4√3 / 8
sin a = 1/2 √3
sin a = 60°
jawabn nomer 5
sin135 = sin (180-45)
= sin 45
= 1/2 √2
luas = 1/2 x a x b x sin 135
= 1/2 x 6 x 10 x 1/2 √2
= 3 x 5√2
= 15√2 cm²
jawabn nomer 6
sudut = 60 : 2= 30
cos 30 = samping/miring
1/2 √3 = AP/5
1/2√3 x 5 = AP
5/2√3 = AP