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titik pusat di (0,0) dan r = √18 = 3√2
b. (x - 3)² + y² = 36
pusat (3,0) dan r (jari-jari) = 6
c. (x - 2)² + (y + 4)² = 25
pusat (2, -4) dan r = 5
d. 2x² + 2y² - 12x - 20y = 12
kedua ruas dibagi 2, get
x² + y² - 6x - 10y = 6
x² + y² - 6x - 10y - 6 = 0
(x - 3)² + (y - 5)² - 34 - 6 = 0
(x - 3)² + (y + 5)² = 40
pusat (3, -5) dan r = √40 = 2√10