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Tentu diperoleh:
Dengan a < b < c
2013 = 3 x 11 x 61
2013 = 1 x 3 x 11 x 61
2013 = 2° x 3¹ x 11¹ x 61¹
Sehingga:
w = 0
a = 3, b = 11, c = 61
x = 1, y = 1, z = 1
Sehingga:
(2w) + (ax) + (by) + (cz)
= (2.0) + (3.1) + (11.1) + (61.1)
= 0 + 3 + 11 + 61
= 75 [D]
2^w · a^x ·b^y · c^z = 2013
1 · 3 · 11 · 61 =2013 ⇒ berdasarkan pemfaktoran
2^0 · 3^1 ·11^1 · 61^1 = 2013
w = 0, a = 3, b = 11, c =61, x = 1, y =1, z =1
2w + ax + by + cz = 2 · 0 + 3·1 + 11·1 + 61·1 = 3 + 11 +61 = 75