Question

Mohon bantuannya ya menjawab:( beserta caranya ya. soalnya sulit:( terima ksih

Answer 1

18. Diket:
Q = 2,25.10⁴ J = 22500 J
Δt = 30 - 0 = 30'c
c = 600 J/kg'c
Dit: m....?
m = Q/c.Δt
m = 22500/600 x 30
m = 22500/18000
m = 1,25 Kg (E)
,
19. Diket:
s = 10cm
Lo = s² = 10² = 100cm²
α = 3x10⁻⁵/'c
β = 2α = 2 x 3 x10⁻⁵/'c = 6 x10⁻⁵
Δt = 20'c
Dit L....?
L = Lo ( 1 + β Δt)
L = 100 ( 1 + 6 x10⁻⁵ . 20)
L = 100 ( 1 + 12 x 10⁻⁴)
L = (100 x 1) + (100 x 12 x 10⁻⁴)
L = 100 + 12 x10⁻²
L = 100 + 0,12
L = 100,12 cm² (C)
,
20 . Diket:
lo = 50 cm
t1 = 27 'c
t2 = 77'c
α = 18 x 10⁻⁶/'c
Dit: l...?
l = lo ( 1 + α (t2 - t1))
l = 50 ( 1 + 18x10⁻⁶ (77-27))
l = 50 ( 1 + 18x10⁻⁶ (50))
l = 50 ( 1 + 9 x10⁻⁴)
l = (50 x 1) + (50x9x10⁻⁴)
l = 50 + 450 x10⁻⁴
l = 50 + 0,045
l = 50,045 cm(D)

Answer 2

18. Dik: Q = = 22500 J
ΔT = 30°C
c = 600 J/kg°C

Dit: m?

Jawab:
Q = m.c.ΔT
22500 = m.600.30
22500 = m.18000
m =

19. Dik: s = 10cm, Ao =
/°C
ΔT = 20°C


Dit: A?
Jawab:
A = Ao (1 + .ΔT
A = 100 (1 + .20
A = 100 (1 + )
A = 100 +
A = 100 + 0,12
A = 100,12

20. Dik: Lo = 50cm
T1 = 27°C
T2 = 77°C
ΔT = 77 - 27 = 50°C
/°C

Dit: L?
Jawab:
L = Lo ( 1 + α.ΔT)
L = 50 ( 1 + .50)
L = 50 ( 1 + )
L = 50 +
L = 50, 045 cm