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3x+4y-5z=12 |x2| 6x+8y-10z=24
2x+5y+z = 17 |x3|6x+15y+3z=51-
-7y-13z=-27......1
2x+5y+z=17 |x3| 6x+15y+3z 51
6x-2y+3z=17 |x1| 6x-2y+3z=17 -
17y =34
y=2
masukan ke pers.1
-7(2)-13z=-27
-14-13z =-27
-13z=-13
z=1
masukan ke persamaan yang ada 3 itu,pilih salah satu.tapi kita pilih yang ke 2
2x+5y+z =17
2x+5(2)+1=17
2x =17-11
2x =6
x =3
jadi (x,y,z)=(3,2,1)
buktikan
2x+5y+z=17
2(3)+5(2)+1=17
6+10+1 =17
17 =17 ---->betul
dit: x²+y²+z²
=3²+2²+1²
=9+4+1
=14 --->hasil