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V1 = 0,025 m³
Po = 10^5 Nm
P1 = 2 x 10^5 Nm
ditanyakan : w ... proses isotermik
ΔP = 2 x 10^5 - 10^5
= 10^5 Nm
ΔV = 0,025 - 0,0125
= 0,0125 m³
w.c _a = 1/2.ΔV ( Po + P1)
= 1/2 . 0,0125 ( 10^5 + 2 x 10^5)
= 1/2 . 125 x 10^-4 ( 3 x 10^5)
= 1/2 . 125 . 3 . 10
= 1875 J
w.a_b = - Po . ΔV ... (Vb < Va)
= - 10^5 . 0,0125
= 1250 J
w.b_c = 0 ..... ( karena volumenya tetap)
w.siklus = w.cabc = wca + w.ab + w.bc
= 1875 - 1250 + 0
= 625 J
b) daya = W/t
= 5 .625 / 2
= 1662,5 watt