Question

Mohon bantuannya :)

sebuah fungsi didefinisikan dengan rumus g(x) = 3x^2 - 16
a. hitunglah g(6) dan g(5)
b jika nilai g(a) = 32 temtukan nilai a

Answer 1

G(x) = 3x^2 - 16
a. g(6) = 3 (6)^2 - 16
     = 3 x 36 - 16
   = 92
g(5) = 3 (5)^2 - 16
     = 3 x 25 - 16
   = 59
b. g(a) = 3a^2 - 16
   32 = 3a^2 - 16
  48 = 3a^2
  16 = a^2
a= 4 atau a= - 4

Answer 2

G(x) = - 16

a. g(6) = 3() - 16 = 3 (36) - 16 = 108 - 16 = 92
g(5) = 3() - 16 = 3 (25) - 16 = 75 - 16 = 59

b. g(a) = - 16
g(a) = 32, maka
32 = - 16
32 + 16 =
48 =
= 48 : 3
= 16
a =
a = 4