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Fa = Fc = 6 N
Fb = 15 N
ιa = 0 m
ιb = 1 m
ιc = 2 m
ΣτA = ....?
momen gaya oleh Fa
τa = Fa x ιa sin θ = 6 x 0 x sin θ = 0
momen gaya oleh Fb
arahnya berlawanan dgn arah jarum jam, maka nilainya negatif
τb = Fb x ιb = 15 x 1 = -15 Nm
momen gaya oleh Fc
τc = Fc x ιc = 6 x 2 = 12 Nm
ΣτA = τa + τb + τc = 0 + (-15) + 12 = -3 Nm
arahnya berlawanan dgn arah jarum jam
2. a = 2 m/s²
g = 10 m/s²
m = 4 kg
r = 10 m
I = ....?
rumus momen inersia bola pejal
I = (2/5) mr²
I = (2/5) 4 (10)² = 160 kgm²