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α = 0
F1 x = F1 cos 0 F1 y = F1 sin 0
= 200,16 = 0
F2 = 300,16 lb kearah kanan diatas sb x 66o
α = 66
F2 x = F2 cos 66 F2 y = F2 sin 66
= 300,16 cos 66 = 300,16 sin 66
= 300,16 . 0,406 = 300,16 . 0,913
= 122 = 274
F3 = 100,16 kearah kekiri diatas sb x 51o
α = 180-51
= 129o
F3 x = F3 cos 129 F3 y = F3 sin 129
= 100,16 . (-0,63) = 100,16. 0,777
= -63,1 = 77,78
F4 = 200,16 vertikal kebawah
α = 270o
F4 x = F4 cos 270 F4 y = F4 sin 270
= 200,16 cos 270 = 200,16 (-1)
= 0 = -200,16
∑F x = F1 x + F2 x + F3 x + F4 x
= 200,16 + 122 - 63,1 + 0
= 259,06 lb
∑F y = F1 y + F2 y + F3 y + F4 y
= 0 + 274 + 77,78 - 200,16
= 151,62 lb
R = √ ∑Fx² + ∑Fy²
= √ 259,06² + 151,62²
= √ 67112,08 + 22988,62
= √ 90100,71
= 300,16 lb