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Verified answer
Pitagorasx = 20 m
h(t) = 10t - t²
maksimum h ' (t) = 0
10 - 2t = 0
t = 5 detik
h maksimum = 10(5) - 5² = 50 - 25
h = 25 m
jarak anak ke balon = r
r² = x² + h²
r² = 20² + 25² = 1025
r = 5√41