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P1 = 2,81×10^5 Ps, T1 = 300 K
P2 = 3,01×10^5 Pa, T2 = __?
volume tetap
Proses Isokorik
P1 / T1 = P2 / T2
T2 = (P2 / P1) T1
T2 = (3,01×10^5 / 2,81×10^5) • 300
T2 = 321 K ← jwb