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Ek₁ = 3 E₀
T₁ = ___ ?
Ek₂ = E₀
T₂ = 7 ºC = 280 K
Ek = ³/₂ k T
Energi kinetik sebanding dengan suhu mutlaknya.
Ek₂ / Ek₁ = T₂ / T₁
T₁ = T₂ × (Ek₁ / Ek₂)
T₁ = 280 × (3E₀ / E₀)
T₁ = 280 × 3 = 840 K = 567 ºC ← jawaban