Usaha gas W = p • ∆V 3×10^5 = p • (2 - 0,5) p = 3×10^5 / (1,5) W = 2×10^5 ← jwb
1 votes Thanks 0
whongaliemdiketahui : v1 = 0,5 m³ v2 = 2 m³ w = 3 x J ditanya : P proses isobarik , berlaku w = P. Δv w = P (v2 - v1) 3 x = P (2 - 0,5) 3 x = P .1,5 P = P = 2 x Pa
• Usaha oleh gas
W = 3×10^5 J
V1 = 0,5 m³
V2 = 2 m³
p = __?
Usaha gas
W = p • ∆V
3×10^5 = p • (2 - 0,5)
p = 3×10^5 / (1,5)
W = 2×10^5 ← jwb
v2 = 2 m³
w = 3 x
ditanya : P
proses isobarik , berlaku
w = P. Δv
w = P (v2 - v1)
3 x
3 x
P =
P = 2 x