(Mohon bantu yah beserta cara kerjanya) secepatnya yah...
jarak titik A ke garis BH pada kubus ABCD.EFGH dengan pankang rusuk 6cm adalah...
a. 4√6 cm b.6√6 cm c. 8√6 cm d. 10√6 cm e. 12√6 cm
whongaliemAB² = BO² x BH² 6² = BO x (6√3) 36 = BO x (6√3) BO = BO = 2√3 AH² = HO x HB (6√2)² = HO x (6√3) 72 = HO x 6√3 HO = HO = 4√3 AO² = HO x BO AO² = 4√3 x 6√3 AO² = 72 AO = √72 AO = 6√2
6² = BO x (6√3)
36 = BO x (6√3)
BO =
BO = 2√3
AH² = HO x HB
(6√2)² = HO x (6√3)
72 = HO x 6√3
HO =
HO = 4√3
AO² = HO x BO
AO² = 4√3 x 6√3
AO² = 72
AO = √72
AO = 6√2