Question

Mohon bantu kak please makasi.

Answer 1

Verified answer

Mean=(15x3)+(28x4)+(41x4)+(54x8)+(67x12)+(80x23)+(93x6) / 60
=45+112+164+432+804+1840+558 /60
=3955/60=65,92
Titik tengah median=½. 60=30
b2=60+61/2=60,5
c=13
N=60
F=19
f=12
Median=b2+c(½N-F/f)
=60,5+13(30-19/12)
=60,5+11,92
=72,42
bo=73,5
d1=23-12=11
d2=23-6=17
l=13
Mo=bo+(d1/(d1+d2)) x l
=73,5+(11/11+17). 13
=73,5+5,11
=78,61
Letak Q1 pd frekuensi=¼. 60=15 (48-60)
Q1=b1+l(iN/4 - F per f)
=47,5+13(1.60/4 - 11 per 8)
=47,5+6,5
=54
Letak Q2 dr frekuensi=½. 60=30 (61-73)
Q2=60,5+13(2.60/4 - 19 /12)
=60,5+11,92
=72,42
Letak Q3=¾.60=45 (74-86)
Q3=73,5+13(3.60/4-31/23)
=73,5+7,91
=81,41