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Nomor 5.
x = 5×2^(-4) × t² × 10^6
⇔x = 5/(2^4) × t² × 10^6
⇔x = (5/16) × t² × 10^6 ....(1)
dan
p/x = 2^(-5) × 10^5
⇔ p = 2^(-5) × 10^5 × x
⇔ p = 1/(2^5)× 10^5 × x
⇔ p = (1/32)× 10^5 × x ..... (2)
Dari (1) dan (2) , kita dapatkan:
p = (1/32) × 10^5 × (5/16) × t² × 10^6
untuk t = 3
→ p = (1/32)× 10^5 × (5/16) × 3² × 10^6
⇔p = (1/32)× 10^5 × (5/16) × 9 × 10^6
⇔p = (1/32)× (5/16) × 9 ×10^(5+6)
⇔p = (1×5×9)/(32×16) × 10^11
⇔p = (45/512)× 10^11
⇔p = (4500/512)× 10^9
⇔p = 8,7890625 × 10^9 (bentuk baku)
atau p = 8789062500
Jawab
Keuntungan perusahaan yang diperoleh
selama 3 tahun adalah 8789062500.
Pembahasan
Nomor 6.
a. 2×8^5 + 5×8^6 = 2×8^5 + 50×8^5
= (2+50)×8^5
= 52 × 8^5
b. 2×7^5 + 3×7^4 = 20×7^4 + 3×7^4
= ( 20 + 3 ) × 7^4
= 23 × 7^4
c. 3×(-5)^6 - 2×(-5)^5 = 3×(-5)^1×(-5)^5 - 2×(-5)^5
= 3×(-5)×(-5)^5 - 2×(-5)^5
= -15×(-5)^5 - 2×(-5)^5
= ( -15 -2)×(-5)^5
= ( -17)×(-5)^5
d. 5×11^3 - 7×11^4 = 5×11^3 - 70×11^3
= ( 5 - 70)×11^3
= -65 × 11^3
☺☺☺☺☺
Selamat Belajar !
@ Wello1