Question

100 ml larutan CH3COOH (mr=60) yang mengandung 30% massa dan berat jenis 1,04 g/ml, dicampurkan dgn x ml larutab CH3COOH 0,3 M shg konsentrasi campuran adlh 0,4 M. Tentukan nilai x

Answer 1

M CH3COOH = % x bj x 1000 / Mr
M CH3COOH = 30% x 1,04 x 1000 / 60 = 5,2 M
v1 = 100 ml
M1 = 5,2 M
v2 = x
M2 = 0,3 M
M campuran = (v1 x M1) + (v2 x M2) / ( v1 + v2)
0,4 = (100 x 5,2) + ( x x 0,3) / ( 100 + x)
40 + 0,4x = 520 + 0,3x
0,1x = 480
x = 4800 ml