Question

Sebanyak 10 gram NaOH dilarutkan dalam 40 gr air sehingga diperoleh larutan dengan massa jenis 1.5 gram/ml. berapakah kemolarannya

Answer 1

Massa NaOH = 10 gram
massa air = 40 gram
massa larutan = 10 + 40 = 50 gram
V larutan = massa larutan / ρ = 50/1,5 = 33,3 mL = 0,0333 L
Mr NaOH = 40

Molaritas
M = (gr/Mr) / V = (10/40) / 0,0333 = 7,508 M