Misalnya : , gimana cara nentuin nilai b-nya?.... Question from @Aurizdwich

September 2018 1 41 Report

Misalnya : $\int\limits^4_b { x^{3} } \, dx = 12$ , gimana cara nentuin nilai b-nya?

masatta $\int\limits^4_b { x^{3} } \, dx$ = 12
$\frac{ x^{4}}{4} \left \{ }{4} \atop {b}} \right.$
$\frac{256}{4}$ - $\frac{ b^{4}}{4}$ = 12
256 - $b^{4}$ = 48
$b^{4}$ = 256 - 48 = 208
b = $\sqrt[4]{208}$

1 votes Thanks 1

Aurizdwich Misalnya : [tex] \int\limits^4_b { x^{3} } \, dx = 12[/tex] , gimana cara nentuin nilai b-nya? kan templatenya : [tex]F(A) -F (B) = 12[/tex] [tex]F( \frac{1}{3} x^{4} ) - F(B) = 12[/tex] [tex]F( \frac{1}{3} 4^{4} ) - F(B) = 12[/tex] [tex]F( \frac{16}{3}) - 12 = F(B)[/tex] [tex]5,3 - 12 = -6,67 [/tex] Bener ga? heheee

Aurizdwich ragu bro

Aurizdwich btw main dota? add steam : rearmivarre tar play bareng wkwk

masatta kok jadi 1/3 sih abis di integralin? kan 1/4 harusnya --> 1/4 x^4.. gak maen dota dulu , mau uas.. wkwk,,,

Aurizdwich ooh, F(A) -F (B) = 12 F( \frac{1}{4} x^{4} ) - F(B) = 12 F( \frac{1}{4} 4^{4} ) - F(B) = 12 F( \frac{256}{4}) - 12 = F(B) 64 - 12 = 52

Aurizdwich btw ini integral tertentu bukan pangkat, btw thanks

masatta kan ada per 4 nya.. masa diilangin gitu aja? trus b nya dimasukkin ke F(B)

Aurizdwich oiya lupa, tapi jadinya kan 64 - b/4 = 12 coret jadi 16 - b = 12 16 - 12 = b b = 4 gimana?

Aurizdwich kalo jawaban yg kamu a sama b nya digabung, kan bukannya kalogasalah harus kan dipisah kaya F(A)=1/4 4^4 =1/4 256 =64 F(B)= b/4 ^4 64 - b/4 ^4 = 12 16 - b^4 = 12 16 -12 = b akar 4 4 = b akar 4 dong?

masatta bentar,, udah diedit..

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