Question

Minta tolong dong.
Itu gimana ya, kalau bisa sama caranya.
Makasih.

Answer 1

Berarti
gradien garis a = ma = (0-4)/(-6-0) = -4/-6 = 2/3
garis a tegak lurus garis b, berarti mb = -1(2/3) = -3/2
garis b ngelewatin titik (-6,0) dan (0,x)
mb = -3/2
(x-0)/(0+6) = -3/2
x / 6 = -3/2
2x = -18
x = -9
garis p juga nglewatin titik (0,-9), garis p sejajar garis a, berarti ma = mp = 2/3
pers garis p =
y + 9 = 2/3 (x-0)
y + 9 = 2/3x
3y + 27 = 2x
2x - 3y - 27 = 0