Question

Minta bantuannya no 11, 12, 13. terima kasih

Answer 1

Y = 2x²(x - 3)
y' = 4x(x - 3) + 2x²(1)
y' = 4x² - 12x + 2x²
y' = 6x² - 12x

4x - 24y - 1 = 0

24y = 4x - 1
y = 4/24 x - 1/24
y = 1/6 x - 1/24

m1 = 1/6
m2 = -6

y' = m2
6x² - 12x = -6
6x² - 12x + 6 = 0
x² - 2x + 1 = 0
(x - 1)(x - 1) = 0

x = 1

y = 2x²(x - 3)
y = 2(1)²(1 - 3)
y = 2(-2)
y = -4

garis melalui (1, -4)

y - b = m(x - a)
y -(-4) = -6(x - 1)
y + 4 = -6x + 6
y = -6x + 2
6x + y = 2
= B.

==========

y = (a + bx⁴)/x²
4 = (a + b(1)⁴)/(1)²
4 = a + b

y - 4 = 0
y = 4
m = 0

y = (a + bx⁴)/x²
y' = (4bx³.x² - (a + bx⁴)2x) / x⁴
y' = (4bx⁵ - 2ax - 2bx⁵) / x⁴
y' = (2bx⁵ - 2ax) / x⁴
0 = (2b(1)⁵ - 2a(1)) / (1)⁴
0 = (2b - 2a)

2b - 2a = 0
b - a = 0

b = a

a + b = 4
a + a = 4
2a = 4
a = 2

b = a = 2

2a - b = 2(2) - 2
= 4 - 2
= 2

==========

y = x³ - 2x² + 3
y = (2)³ - 2(2)² + 3
y = 8 - 8 + 3
y = 3

garis menyinggung di titik (2, 3)

y = x³ - 2x² + 3
y' = 3x² - 4x

y' = m
3x² - 4x = m
3x² - 4x - m = 0
3(2)² - 4(2) - m = 0
12 - 8 - m = 0
4 - m = 0
m = 4

m2 = -1/4

y - b = m(x - a)
y - 3 = -1/4(x - 2)
4y - 12 = -(x - 2)
4y = -x + 2 + 12
4y = -x + 14
x + 4y - 14 = 0