Miejscem zerowym funkcji jest liczba??
Proszę dobrze rozpisać :)
f(x) = 2(x + 3) + 3(x + 2)
F(X) = 0
2(x + 3) + 3(x + 2) = 0
2x + 6 + 3x + 6 = 0
5x + 12 = 0
5x = -12 /:5
x = -12/5
x = -2 i 2/5 -------- odpowiedx
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f(x) = 2(x + 3) + 3(x + 2)
F(X) = 0
2(x + 3) + 3(x + 2) = 0
2x + 6 + 3x + 6 = 0
5x + 12 = 0
5x = -12 /:5
x = -12/5
x = -2 i 2/5 -------- odpowiedx