Miejscami zerowymi funkcji kwadratowej są liczby -6 i 1.
Oblicz (ułamek) -> 3×f(94) ÷ f(-24)
x1 = -6 ; x2 = 1
zatem
f(x) = a*(x +6)(x -1)
f(94) = a*(94 +6)*(94-1) = 93*100*a
f(- 24) = a*(-24 +6)*(-24 -1) = a*(-18)*(-25)= 25*18*a
czyli
[3 *f(94)]/[f(-24)] = [3 *93*100*a]/[25*18*a] = [93*4]/6 = 62
Odp. 62
=============
X1 = -6
X2 =1
f(x) =a(x+6)(x-1)
3 * f(94):f(-24)
f(94) =a(94+6)(94-1)
f(94) =100 * 93a
f(-24)=a(-24+6)(-24-1)
f(-240 =(-18)(-25)a
f(-24) =18 *25a
3 *f(94):f(-24)=
=3 *100 *93a:18 *25a =
=93 *4:6 = 62
Odp.Ułamek 3*f(94):f(-24) = 62
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x1 = -6 ; x2 = 1
zatem
f(x) = a*(x +6)(x -1)
f(94) = a*(94 +6)*(94-1) = 93*100*a
f(- 24) = a*(-24 +6)*(-24 -1) = a*(-18)*(-25)= 25*18*a
czyli
[3 *f(94)]/[f(-24)] = [3 *93*100*a]/[25*18*a] = [93*4]/6 = 62
Odp. 62
=============
X1 = -6
X2 =1
f(x) =a(x+6)(x-1)
3 * f(94):f(-24)
f(94) =a(94+6)(94-1)
f(94) =100 * 93a
f(-24)=a(-24+6)(-24-1)
f(-240 =(-18)(-25)a
f(-24) =18 *25a
3 *f(94):f(-24)=
=3 *100 *93a:18 *25a =
=93 *4:6 = 62
Odp.Ułamek 3*f(94):f(-24) = 62