Metoda podstawiania proszę o rozwiązanie bo mi wychodzą ułamki na końcu-_-
\left \{ {{y=2x+1} \atop {4x+y=13}} \right.
y = 2x + 1
więc:
4x + y = 13
4x + 2x + 1 = 13/-1
6x = 12 / :6
x = 2
y=2x+1
4x+2x+1=13
6x+1=13
6x=12
x=2
y=4+1
y=5
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y = 2x + 1
więc:
4x + y = 13
4x + 2x + 1 = 13/-1
6x = 12 / :6
x = 2
y=2x+1
4x+2x+1=13
y=2x+1
6x+1=13
y=2x+1
6x=12
y=2x+1
x=2
y=4+1
x=2
x=2
y=5