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T₁=627°C =627+273=900 K
T₂=27°C=27+273=300 K
Q₁=1000 kkal
Ditanyakan: Q₂?
Dijawab:
Gunakan rumus efisiensi mesin:
η= 1-T₂ ...[1]
T₁
η= W
Q₁
=Q₁-Q₂
Q₁
=1-Q₂.........[2]
Q₁
Masukan persamaan keatas dengan substitusi:
1-Q₂ = 1-T₂
Q₁ T₁
T₂ =Q₂
T₁ Q₁
300 = Q₂
900 1000
900Q₂=300000
Q₂=300000
900
=333,3 kkal
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