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BC = √AB² - AC²
BC = √20² - 12²
BC = √400 - 144
BC = √256
BC = 16 cm
Luas Segitiga = 1/2 x alas x tinggi
= 1/2 x 16 x 12
= 8 x 12
= 96 cm²
*Mencari Luas 1/2 Lingkaran
Luas Lingkaran = 1/2 x π x r²
r = diameter ÷ 2
r = 20 ÷ 2
r = 10 cm
= 1/2 x 3,14 x 10²
= 1/2 x 3,14 x 100
= 1/2 x 314
= 157 cm²
Luas Daerah Yang Diarsir = Luas 1/2 Lingkaran - Luas Segitiga
= 157 cm² - 96 cm²
= 61 cm²
Jadi, jawabannya adalah b. 61
# Semoga Membantu
BC = √400 - 144
BC = √256
BC = 16 CM
L segitiga = 1/2 × a × t
= 1/2 × 12 × 16
= 96 cm²
L lingkaran total = πr²
= 3,14 × 10 × 10
= 314 cm²
L 1/2 lingkaran = 1/2πr²
= 1/2 × 3,14 ×10 × 10
= 157 cm²
Luas daerah yang diarsir :
= 314 - 157 - 96
= 61 cm² (B)