Question

Melalui titik r (5,8) garis tegak lurus 2x-3y-2=0

Answer 1

M=-a/b
-2/-3 =m1
tegak lurus m1*m2=-1
-2/3*x=-1
m2=3/2

(5,8)
y-y1=m(x-x1)
y-8= 3/2(x-5)
y-8=3/2x-15/2
2y-16=3x-15
2y-3x-1=0

Answer 2

2x - 3y - 2 = 0
2x - 2 = 3y
y = 2/3 x - 2/3
gradien = 2/3
gradien tegak lurusnya = -3/2
y - 8 = -3/2(x-5)
y - 8 = -3/2 x + 15/2
y = -3/2 x + 31/2
2y = -3x + 31
2y +3x - 31 = 0