Question

Me responden la consigna 3 y 4 pls

Answer 1

Respuesta:

Explicación paso a paso:

consigna 3. resuelva las siguientes restas de fracciones en que los denominadores son iguales.

1) [tex]\frac{12}{10}- \frac{4}{10}= \frac{12-4}{10}= \frac{8}{10}= \frac{4}{5}[/tex]

2) [tex]\frac{9}{100} -\frac{7}{100}= \frac{9-7}{100}= \frac{2}{100}= \frac{1}{50}[/tex]

3) [tex]\frac{9}{12}- \frac{8}{12}= \frac{9-8}{12}= \frac{1}{12}[/tex]

4) [tex]\frac{2}{3}+ \frac{5}{3} =\frac{7}{3}[/tex]

5) [tex]\frac{7}{8}- \frac{5}{8}= \frac{1-5}{8}= \frac{2}{8}= \frac{1}{4}[/tex]

6)  [tex]\frac{6}{24}- \frac{4}{24}= \frac{6-4}{24}= \frac{2}{24}=\frac{1}{12}[/tex]

7) [tex]\frac{16}{6}- \frac{9}{6}= \frac{16-9}{6}= \frac{7}{6}[/tex]

consigna 4. resuelve las siguientes restas de fracciones en la que el denominador es diferente.

1) [tex]\frac{3}{5} - \frac{2}{10}= \frac{3}{5}-\frac{1}{5} \frac{3-1}{5} =\frac{2}{5}[/tex]

2) [tex]\frac{1}{2} -\frac{1}{8} = \frac{4-1}{8} = \frac{3}{8}[/tex]

3) [tex]\frac{18}{6}- \frac{24}{12}= 3- \frac{24}{12}= 3-2 = 1[/tex]

4) [tex]\frac{9}{10}- \frac{1}{2}= \frac{9}{5}= \frac{4}{10}= \frac{2}{5}[/tex]

5) [tex]\frac{9}{12} -\frac{2}{3} = \frac{9-8}{12} = \frac{1}{12}[/tex]

6) [tex]\frac{13}{4}- \frac{5}{8}= \frac{26-5}{8}= \frac{21}{8}[/tex]

7) [tex]\frac{2}{3}- \frac{4}{6}= \frac{2}{3} -\frac{2}{3}= 0[/tex]

8) [tex]\frac{1}{3}- \frac{1}{12}= \frac{4-1}{12}=\frac{3}{12} = \frac{1}{4}[/tex]

9) [tex]\frac{19}{14}- \frac{5}{7}= \frac{19-10}{14} = \frac{9}{14}[/tex]

10) [tex]\frac{50}{100}- \frac{4}{10}= \frac{5}{10}- \frac{4}{10}= \frac{5-4}{10}= \frac{1}{10}[/tex]