cilindro A:
H=10
D=6
r=3
Area lateral=[tex]2.\pi .3.10=60\pi[/tex]
Area total=[tex]2.\pi .3.10+2.\pi .3^{2}=78\pi ^{2}[/tex]
cilindro B:
H=750 cm
r=5
Area lateral=750[tex]\pi[/tex]
Area total=800[tex]\pi[/tex]
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Verified answer
cilindro A:
H=10
D=6
r=3
Area lateral=[tex]2.\pi .3.10=60\pi[/tex]
Area total=[tex]2.\pi .3.10+2.\pi .3^{2}=78\pi ^{2}[/tex]
cilindro B:
H=750 cm
r=5
Area lateral=750[tex]\pi[/tex]
Area total=800[tex]\pi[/tex]