" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
primero la parte izquierda la dejamos en terminos de senos y cosenos
sen A + cos A = sec A csc A
cos A sen A
sen A(sen A) + cos A(cos A) = sec A csc A
cos A sen A
sen² A + cos² A = sec A csc A
cos A sen A
identidad pitagorica sen²A + cos² A = 1
1 = sec A csc A
cos A sen A
1 1 = sec A csc A
cos A sen A
sec A csc A = sec A csc A
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
sen³x cosx + cos³x senx = senx cosx
sacamos factor comun:
senx cosx (sen²x+cos²x) = senx cosx sen²x+cos²x=1
senx cosx (1) = senx cosx
senx cosx = senx cosx