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80 = (2^4)(5)
220 = (2^2)(5)(11)
Entonces los divisores serán las diferentes combinaciones que se consigan.
Todos son divisibles entre:
2 y 5; estos son los dos únicos divisores que dan resultados enteros.
15 |3
5 |5
1
1 2
3 6
5 10
15 30
25 50
75 150
150= 1,2,3,5,6,10,15,25,30,50,75,150
80|2×5
8|2^3
1 2 4 8 16
5 10 20 40 80
80= 1,2,4,5,8,10,16,20,40,80
220|5×2
22|2
11 |11
1
1 2 4
5 10 20
11 22 44
55 110 220
220= 1,2,4,5,10,11,22,44,55,110,220