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4x-5y=10
-5y=10-4x
y=(4x-10)/5
Luego reemplazamos ese valor en la primera
ax+3((4x-10)/5)=5
ax+3((4x-10)/5)-5=0
(5ax+12x-30-25)/5=0
5ax+12x-30-25=0
5ax+12x-55=0
5ax+12x=55
x(5a+12)
Entonces:
5a+12=0
5a=-12
a= -12/5
El sistema es incompatible en -12/5
Saludos :D