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1)
2π/5 + Ф = π/2
Ф = π/2 - 2π/5
Ф = π/10
2)
2C - S = 11
2(10n) - 9n = 11
20n-9n = 11
11n = 11 ------> n = 1
entonces S = 9×1 ------> S = 9
Nos piden R, luego de la relación de sistemas de medidas angulares,
S/180 = R/π
9/180 = R/π ----------> R = π/20
3)
S = X+4
C = X+5
de la relación:
S/9 = C/10 , REEMPLAZAMOS
X+4 /9 = X+5 /10 , desarrollando obtrenemos el valor de x, seria
10x+40 = 9x+45
x = 5
luego: S = 5+4 --------> S = 9
Nos piden R, entonces de la relación:
S/180 = R/π
9/180 = R/π --------> R = π/20