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1) biar mudah diketik, vektornya di ubah ke dalam bentuk vektor basisx = 5i + 6j, y = 3i + 3j dan z = 7i + 6j
a) 5x - 2y - z
= 5(5i + 6j) - 2(3i + 3j) - (7i + 6j)
= 25i + 30j - 6i - 6j - 7i - 6j
= 12i + 18j
= (12)
.. (18)
b) 2x + 1/3 y - 1/2 z
= 2(5i + 6j) + 1/3 (3i + 3j) - 1/2 (7i + 6j)
= 10i + 12j + i + j - 7/2 i - 3j
= 15/2 i + 10j
= (15/2)
.. (..10..)
2) diketahui : P(2, 3), Q(12, -7), R(x, y)
PR = 1/5 PQ
a. PQ = q - p = (12, -7) - (2, 3) = (10, -10) = 10i - 10j
b. PR = 1/5 PQ = 1/5 (10, -10) = (2, -2) = 2i - 2j
c. PR = (2, -2)
r - p = (2, -2)
r = (2, -2) + p
r = (2, -2) + (2, 3)
r = (4, 1)
Jadi koordinat R (4, 1)
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VektorMatematika XII
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