Question

Materi pelajaran kelas 10. bisa tolong dibantu dgn cara ya. terimakasih

Answer 1

Jawaban:

[(9/25)^(x²+4x)] [(125/27)^(x+4)]= 1

[(3²/5²)^(x²+4x)] [(5³/3³)^(x+4)]= 1

[(3/5)^2(x²+4x)] [(5/3)^3(x+4)]= 1

[(3/5)^2(x²+4x)] [(3/5)^-3(x+4)]= 1

(3/5)^(2(x²+4x)-3(x+4)) = 1

(3/5)^(2x²+8x-3x-12) = 1

(3/5)^(2x²+5x-12)=1

(3/5)^(2x²+5x-12)= (3/5)^0

=> 2x²+5x-12 =0

=> (2x-3)(x+4)=0

=> x2= 3/2 atau x1=-4

x1- 2 x2= -4-2(3/2)

= -4-3

=-7