Question

Matematyka z plusem 3 ;> ...chyba łatwe...

zad 8 str 111.

Oblicz obwód czworokąta o wierzchołkach:
A=(-2,1). B=(1,-5), C=(4,1), D=(1,3).

Czy wiesz jak się nazywa ten czworokąt??

Dam naj. ;>

Answer 1

I AB I^2  = (1 - (-2))^2 + (-5 - 1)^2 = 3^2 + (-6)^2 = 9 + 36 = 45 = 9*5

I AB I = 3 p(5)

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I BC I^2 = ( 4 - 1)^2 + (1 - (- 5))^2 = 3^2 + 6^2 = 9 + 36 = 45

I BC I = 3 p(5)

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I CD I^2 = (1 - 4)^2 + (3 - 1)^2 = (-3)^2 + 2^2 = 9 + 4 = 13

I CD I = p (13)

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I AD I^2 = (1 - (-2))^2 + (3 - 1)^2 = 3^2 + 2^2 = 9 + 4 = 13

I AD I = p(13)

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Obwód

L = 2* 3 p(5) + 2* p(13) = 6 p(5) + 2 p(13)

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Ten czworokąt to deltoid.

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