Matematyka z plusem 2 zadanie 29 strone 92 błagaam pomóżcie nie chce dostac 3 jedynki z zadania domowego pliss. ;(
http://zadane.pl/zadanie/3227388 ;)
2(x-y)(x+y)- (x-2y)^2 = 2( x^2 -xy - xy +y^2) -[(x-2y)(x-2y)] = =2x^2 -2y^2 - [x^2 -2xy -2xy+4y^2] = 2x^2 -2y^2 - x^2 +4xy -4y^2 = x^2 +4xy -6y^2
(2a-b)^2 - 2 (a-b)(2a+b)= (2a-b)(2a-b) -(2a^2 +ab -2ab -b^2)=
=4a^2 -2ab- 2ab -b^2 -2a^2 -ab +2ab +b^2=2a^2 -3ab
5(s+3t)(3t-s) - (s+2t)^2 = 5( 3st -s^2 +9t^2 -3st) - [(s+2t)(s+2t)]=
= -5s^2 + 45t^2 - [s^2 + 4st+4t^2] = -5s^2 + 45t^2 - s^2 - 4st - 4t^2=
=-6s^2+41t^2 -4st
(z +0,3)^2 + (z+0,2)(0,2-z) =( z+0,3)(z+0,3) + 0,2z -z^2 +0,04 -0,2z=
=z^2 +0,6z- 0,09 - z^2 +0,04 = 0,6z -0,13
2( (a+b)/2 )^2 - 2(a/2+b)(b+a/2)= 2 (a+b)^2/4 -2(ab/2 +a^2/4 +b^2 + ab/2)=
= (a^2 +2ab+b^2)/2 - ab -a^2/2 - 2b^2 -ab=a^2/2 + ab +b^2/2 - ab -a^2/2 - 2b^2 -ab = - ab - 3/2 b^2
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2(x-y)(x+y)- (x-2y)^2 = 2( x^2 -xy - xy +y^2) -[(x-2y)(x-2y)] = =2x^2 -2y^2 - [x^2 -2xy -2xy+4y^2] = 2x^2 -2y^2 - x^2 +4xy -4y^2 = x^2 +4xy -6y^2
(2a-b)^2 - 2 (a-b)(2a+b)= (2a-b)(2a-b) -(2a^2 +ab -2ab -b^2)=
=4a^2 -2ab- 2ab -b^2 -2a^2 -ab +2ab +b^2=2a^2 -3ab
5(s+3t)(3t-s) - (s+2t)^2 = 5( 3st -s^2 +9t^2 -3st) - [(s+2t)(s+2t)]=
= -5s^2 + 45t^2 - [s^2 + 4st+4t^2] = -5s^2 + 45t^2 - s^2 - 4st - 4t^2=
=-6s^2+41t^2 -4st
(z +0,3)^2 + (z+0,2)(0,2-z) =( z+0,3)(z+0,3) + 0,2z -z^2 +0,04 -0,2z=
=z^2 +0,6z- 0,09 - z^2 +0,04 = 0,6z -0,13
2( (a+b)/2 )^2 - 2(a/2+b)(b+a/2)= 2 (a+b)^2/4 -2(ab/2 +a^2/4 +b^2 + ab/2)=
= (a^2 +2ab+b^2)/2 - ab -a^2/2 - 2b^2 -ab=a^2/2 + ab +b^2/2 - ab -a^2/2 - 2b^2 -ab = - ab - 3/2 b^2