Zadanie 2
[tex]d) 2=\sqrt{4}, wiec 2\sqrt{2}=\sqrt{4}*\sqrt{2}=\sqrt{4*2}=\sqrt{8}\\ e) 3=\sqrt{9}, wiec 3\sqrt{2}=\sqrt{9}*\sqrt{2}=\sqrt{9*2}=\sqrt{18}\\ f) 7=\sqrt{49}, wiec 7\sqrt{3}=\sqrt{49}*\sqrt{3}=\sqrt{49*3}=\sqrt{147}[/tex]
Zadanie 3
[tex]a) \sqrt{63}=\sqrt{9*7}=\sqrt{9}*\sqrt{7}=3\sqrt{7}\\ b) \sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}\\ c) \sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}\\ d) \sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}[/tex]
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Zadanie 2
[tex]d) 2=\sqrt{4}, wiec 2\sqrt{2}=\sqrt{4}*\sqrt{2}=\sqrt{4*2}=\sqrt{8}\\ e) 3=\sqrt{9}, wiec 3\sqrt{2}=\sqrt{9}*\sqrt{2}=\sqrt{9*2}=\sqrt{18}\\ f) 7=\sqrt{49}, wiec 7\sqrt{3}=\sqrt{49}*\sqrt{3}=\sqrt{49*3}=\sqrt{147}[/tex]
Zadanie 3
[tex]a) \sqrt{63}=\sqrt{9*7}=\sqrt{9}*\sqrt{7}=3\sqrt{7}\\ b) \sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}\\ c) \sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}\\ d) \sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}[/tex]