Question

Matematyka ! dwa zadanka krótkie !

załączniki !

20 i 21

Answer 1

zad.1

 

22%=0,22

                   0,22 x=(0,9⁻¹+0,3⁻²)·10⁻¹

                   0,22x=[ (9/10)⁻¹+(3/10)⁻²]·10⁻¹

                   0,22x=[10/9+(10/3)²]·1/10

                   0,22x=(10/9+100/9)·10⁻¹

                   0,22x=110/9·1/10=11/9

                          x=11/9:0,22=11/9:22/100=11/9·100/22

                          x=100/18=50/9

  Ta liczba to=  x=5 i 5/9

 

 

zad.2a/   a=(1 1/7)⁻¹+(1 1/3)⁻²=(8/7)⁻¹+(4/3)⁻²=7/8+(3/4)²=7/8+9/16=14/16+9/16=23/16

               a=23/16

               b= 2⁻²+(2 2/3)⁻¹=(1/2)²+(8/3)⁻¹=1/4+3/8=2/8+3/8=5/8

               b=5/8

 

               a:b=?

               23/16: 5/8=23/16·8/5=23/10=23/10x100%=2300/10%=230%

 

 

Liczba a jest większa od liczby b o 230%.

 

zad. 2b/

 

                       5⁴·5²              5⁴⁺²            5⁶             5⁶

              a = ------------- = -------------- = ---------  = -------  = 5⁶⁻⁵=5¹=5

                      (5²)⁴:5³            5²·⁴⁻³         5⁸⁻³          5⁵

 

              a=5

 

                       16·3⁵·2⁷            2⁴·3⁵·2⁷         2⁴⁺⁷ ·3⁵         2¹¹· 3⁵

               b = -----------------  = --------------- = ------------- = ------------ =  2¹¹⁻¹² ·3⁵⁻³=2⁻¹·3²=1/2·9=9/2

                       (2³)²·27·2⁶         2³·²·3³·2⁶       2⁶⁺⁶ ·3³          2¹² ·3³

 

               b= 9/2

 

           a:b=?

 

             5: 9/2= 5·2/9=10/9=1,11 ·100%= 111%

 

            Liczba a jest większa od liczby b o 111 %.