Odpowiedź:
5.31
a = x - r > 0
b = x
c = x + r
Mamy a² + b² = c²
czyli
( x - r)² + x² = ( x + r)²
x² + 2r x + r² + x² = x² + 2 r x + r²
x² = 4r x / : x
x = 4 r
więc
a = 4 r - r = 3 r b = 4 r
Pole Δ
P = 0,5 a*b = 0,5*3r*4r = 6 r² = 2 400 / : 6
r² = 400
r = 20
a = 3*20 = 60
b = 4*20 = 80
c = x + r = 4 r + r = 5 r = 5*20 = 100
Odp. 60,80,100
===================
5.32
Z z. 5.31 mamy
a = 3 r b = 4 r c = 5 r
P = 0,5* 3 r* 4 r = 6 r²
p = (a + b +c) : 2 = 12 r : 2 = 6 r
Korzystamy z wzoru:
P = p*R
R = [tex]\frac{P}{p} = \frac{6 r^{2} }{6 r} = r[/tex]
R = r
=====
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Odpowiedź:
5.31
a = x - r > 0
b = x
c = x + r
Mamy a² + b² = c²
czyli
( x - r)² + x² = ( x + r)²
x² + 2r x + r² + x² = x² + 2 r x + r²
x² = 4r x / : x
x = 4 r
więc
a = 4 r - r = 3 r b = 4 r
Pole Δ
P = 0,5 a*b = 0,5*3r*4r = 6 r² = 2 400 / : 6
r² = 400
r = 20
a = 3*20 = 60
b = 4*20 = 80
c = x + r = 4 r + r = 5 r = 5*20 = 100
Odp. 60,80,100
===================
5.32
Z z. 5.31 mamy
a = 3 r b = 4 r c = 5 r
więc
P = 0,5* 3 r* 4 r = 6 r²
p = (a + b +c) : 2 = 12 r : 2 = 6 r
Korzystamy z wzoru:
P = p*R
R = [tex]\frac{P}{p} = \frac{6 r^{2} }{6 r} = r[/tex]
R = r
=====
Szczegółowe wyjaśnienie: