Question

#matematika wajib kls10

Answer 1

Verified answer

Fungsi
Kelas X


√(x² - 8x + 12) > 0
x² - 8x + 12 > 0
(x - 6)(x - 2) > 0
x < 2 atau x > 6

Domain : {x | x < 2 atau x > 6 , x ∈ R}




√5 = √(a² - 8a + 12)
5 = a² - 8a + 12
a² - 8a + 7 = 0
(a - 7)(a - 1) = 0
a = 7 atau a = 1