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f^-1(x) = x² - 2x +1
y = x² - 2x + 1
x² - 2x = y - 1
(x - 1)² - 1 = y - 1
(x - 1)² = y - 1 + 1
x = √y + 1
f⁻¹(x) = √y+ 1
Jadi, f⁻¹(4) = √4 + 1
= 2 + 1 = 3