Odpowiedź:
a) [tex]\frac{16a^2}{8} -\frac{40}{8} =2a^2-5[/tex]
b) [tex]\frac{-30xy}{5} +\frac{15x}{5} =-6xy+3x[/tex]
c) [tex]\frac{15p^2}{3} -\frac{6p}{3} +\frac{3}{3} =5p^2-2p+1[/tex]
d) [tex]\frac{-8x^2}{4} -\frac{20x}{4} +\frac{12xy}{4} =-2x^2-5x+3xy[/tex]
e) [tex]\frac{21y^2}{7} -\frac{7xy}{7} +\frac{14}{7} =3y^2-xy+2[/tex]
f) [tex]\frac{18a^2}{2}-\frac{30ab}{2} +\frac{4b}{2} =9a^2-15ab+2b[/tex]
g) [tex]\frac{30x^2}{10} -\frac{10xy}{10} +\frac{70}{10} =3x^2-xy+7[/tex]
h) [tex]-\frac{12u^2}{3} -\frac{15uw}{3} +\frac{18u}{3} =-4u^2-5uw+6u[/tex]
i) [tex]\frac{-4}{-2} -(\frac{14p}{-2} )-(\frac{2p^2}{-2} )=2+7p+p^2[/tex]
j) [tex]\frac{9r^2}{-9}-(\frac{27rw}{-9} )-(\frac{45}{-9} )=-r^2+3rw+5[/tex]
Szczegółowe wyjaśnienie:
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Odpowiedź:
a) [tex]\frac{16a^2}{8} -\frac{40}{8} =2a^2-5[/tex]
b) [tex]\frac{-30xy}{5} +\frac{15x}{5} =-6xy+3x[/tex]
c) [tex]\frac{15p^2}{3} -\frac{6p}{3} +\frac{3}{3} =5p^2-2p+1[/tex]
d) [tex]\frac{-8x^2}{4} -\frac{20x}{4} +\frac{12xy}{4} =-2x^2-5x+3xy[/tex]
e) [tex]\frac{21y^2}{7} -\frac{7xy}{7} +\frac{14}{7} =3y^2-xy+2[/tex]
f) [tex]\frac{18a^2}{2}-\frac{30ab}{2} +\frac{4b}{2} =9a^2-15ab+2b[/tex]
g) [tex]\frac{30x^2}{10} -\frac{10xy}{10} +\frac{70}{10} =3x^2-xy+7[/tex]
h) [tex]-\frac{12u^2}{3} -\frac{15uw}{3} +\frac{18u}{3} =-4u^2-5uw+6u[/tex]
i) [tex]\frac{-4}{-2} -(\frac{14p}{-2} )-(\frac{2p^2}{-2} )=2+7p+p^2[/tex]
j) [tex]\frac{9r^2}{-9}-(\frac{27rw}{-9} )-(\frac{45}{-9} )=-r^2+3rw+5[/tex]
Szczegółowe wyjaśnienie: