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c = 4.200 J/kg
Δt = 100°C - 25°C = 75°C
- Ditanya : Q
- Jawab :
Q = m × c × Δt
= 400 × 4.200 × 75
= 126.000.000 J
= 126.000 kJ.
Jadi, jumlah kalor yang diperlukan adalah 126.000 kJ.