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f(x) = 3x³ - 2x² + 2x + 1
g(x + 6) = 5x + 2
ditanya:
a) (fog)-'(x) = ...
b) (fog)-'(1) = ...
jawab:
g(x + 6) = 5x + 2, subs x->x-6
g((x-6) + 6) = 5(x-6) + 2
g(x) = 5x - 28
a) fog = f(g) = 3g³ - 2g² + 2g + 1
= 3(5x - 28)³ - 2(5x - 28)² + 2(5x - 28) + 1
b) (fog)-'(1) = m
↔ fog(m) = 1
3(5m - 28)³ - 2(5m - 28)² + 2(5m - 28) + 1 = 1
↔ (5m - 28) = 0
↔ m = 28/5
(fog)-'(1) = 28/5
maaf kl salah