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POH= M x valensi basa
pH= 14 - POH
d. POH = 0.01 X 2 = 0,02
2x 10^-2
2- log2
ph 14-2(-log2)
12+log2
KOH 0,01 M
POH= 0,01x 1= 0,01
=10^-2
pH 14-2 =12
JADI D maaf aku agak lupa