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b=a+r
c=a+6r
a+b+c=93
b²=ac
a+a+r+a+6r=93
(a+r)²=a(a+6r)
3a+7r=93
a²+2ar+r²=a²+6ar
r²=4ar=0
r(r-4a)=0
jeżeli r=0→a=b=c=31
jeżeli r=4a→3a+28a=93→a=3→r=4a=12
b=a+r=15 i c=a+6r=75
odp. te liczby to:31,31,31 lub 3,15 i 75