Question

Maka x+y adalah....

please can you help me

Answer 1

3^(x + 1) - 3.2^y = 3

bagi dengan 3

3^x - 2^y = 1
3^x = 1 + 2^y

2.3^x + 2^y = 10
2(1 + 2^y) + 2^y = 10
2 + 2.2^y + 2^y = 10
3.2^y = 8
2^y = (8/3)
y = (2)log(8/3)


3^x = 1 + 2^y
3^x = 1 + 2^((2)log(8/3))
3^x = 1 + 8/3
3^x = 11/3
x = (3)log(11/3)

x + y = (3)log(11/3)  + (2)log(8/3)
= (3)log11 - (3)log3 + (2)log8 - (2)log3
= (3)log11 - 1 + 3 - (2)log3
= (3)log11 - (2)log3 + 2

N.B. : 3 dan 2 itu basis logaritmanya ya.

Answer 2

(x+1).³log 3 - ³log 3 - y.³log 2 = ³log 3
x - y.³log 2 = 1..................1

³log 2 + x.³log 3 + y.³log 2 = ³log 10
x + y.³log 2 = ³log 5.....................2

eliminasi y:
x -  y.³log 2 = 1
x + y.³log 2 = ³log 5 (+)
              2x = 1+³log 5
                x = (1+³log 5)/2
                x = ⁹log 15

eliminasi x:
x + y.³log 2 = ³log 5
x -  y.³log 2 = 1  (-)
    2y.³log 2 = ³log 5 - 1
                y = (³log 5 - 1)/(2.³log 2)
                y = ⁴log (5/3)

x+y = ⁹log 15 + ⁴log (5/3)