x-halinki
3+x-magdy
3+x+x-kaja
3+x+x+3+x=x
3x+6=x
3x-x=-6
2x=-6/2
x=-3-halinki
3+3=6-magdy
2*3+3=6+3=9 kaja
halina ma 3 batony
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x-halinki
3+x-magdy
3+x+x-kaja
3+x+x+3+x=x
3x+6=x
3x-x=-6
2x=-6/2
x=-3-halinki
3+3=6-magdy
2*3+3=6+3=9 kaja
halina ma 3 batony