Question

Maaf. tolong bantu lagi no. 19

Answer 1

OC² = BC² - OB²
OC² = 10² - 8²
OC² = 100 - 64
OC² = 36
OC  = 6 cm

maka,
d₁ = BD = 16 cm
d₂ = AC = 15 + 6 = 21 cm

luas layang-layang = 1/2 x d₁ x d₂
                            = 1/2 x 16 x 21
                            = 168 cm² (B)

semoga membantu ya :)

Answer 2

BO = 1/2 BD
BO = 1/2 * 16
BO = 8 cm

panjang CO = √BC² - BO²
= √10² - 8²
= √100 - 64
= √36
CO = 6 cm

panjang diagonal 1 = 16 cm
panjang diagonal 2 = 6 + 15 = 21 cm

luas layang-layang = 1/2 d1 d2
= 1/2 * 16 * 21
= 8 * 21
= 168 cm²